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#复杂度为n平方
def MaxSubseqSum1(A , N ):ThisSum=0MaxSum = 0for i in range(0,N):ThisSum=0for j in range(i,N):ThisSum+=A[j] if ThisSum>MaxSum: MaxSum=ThisSum print( MaxSum)
A=[ -2, 11, -4, 13, -5, -2 ]
N=len(A) t= MaxSubseqSum1(A , N )#复杂度更低 n 在线处理
def MaxSubseqSum1(A , N ):
ThisSum=0MaxSum = 0for i in range(0,N):ThisSum+=A[i]if ThisSum>MaxSum: MaxSum=ThisSum elif ThisSum<0: ThisSum=0 print( MaxSum)
A=[ -1, 3, -2, 4, -6, 1,6,-1 ]
N=len(A) t= MaxSubseqSum1(A , N )转载于:https://blog.51cto.com/13930723/2362589